Question

The length of a rectangle is shown below:

On a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis, two points A and B are shown. The point A is on ordered pair 1, 2, and the point B is on ordered pair negative 2, 2. A straight line joins the points A and B.

If the area of the rectangle to be drawn is 12 square units, where should points C and D be located, if they lie vertically below the line that connects B and A, to make this rectangle?

C(−2, −1), D(1, −1)
C(−2, −4), D(1, −4)
C(−2, −2), D(1, −2)
C(−2, −5), D(1, −5)

Answer 1

A (1,2)
B (-2,2)

12 square units, meaning that's the total area in the rectangle, now the square units of \(\overline{AB}\) is 3, so what times 3 would get you to 12? , 4, so the coordinates for C would be [from B]:
\((-2-0,2-4)\)
so point C would be \((-2,-2)\)
now the same thing for point D,
\((1-0,2-4)\)
so that would mean your point for D would be \((1,-2)\)

that gives you your answer, C\((-2,-2)\) , D\((1,-2)\)