math help ss below
@AZ is this right?
oh wait im wrong! it should be the candy that is left
Hmmm no Each one assumes that they are the first to arrive since the ratio is 3:2:1 that means Albert takes 1/2 Bert takes 1/3 Carl takes 1/6
If Al came first, he would take half then Bert comes and he takes 1/3 of the remaining half so he takes 1/6 of the total and so that means there's 1 - 1/2 - 1/6 = 2/6 = 1/3 left from the original amount
Does that make sense? Now Carl is going to come and take 1/6 of the remaining 1/3 (since he thinks he's the first one there) and so how much does Carl get from the original amount and then how much is left over
so he takes 1/2+1/6+1/18?
another way to think about it is after Al comes, there's 1/2 left after Bert comes, there's 2/3 left after Carl comes, there's 5/6 left and since they all think they're first, you just multiply the three numbers and it doesn't matter who comes first because you're just multiplying
al takes 1/2 al leaves 1/2 bert takes 1/3 of 1/2 so 1/6 carl 5/6 left takes 1/6 of that 5/36 would this work? also would tha answer be 13/18 then?
no, that wouldn't work because remember al took 1/2 of the original amount himself Bert takes 1/3 of the 1/2 which is 1/6 of the total original amount so you need to subtract 1/6 and 1/2 from the original amount of 1 or since Bert is taking 1/3 of the 1/2 Think of it like a pie Half of it is gone and now the remaining half is cut into thirds. Bert takes 1/3 so that leaves 2/3 left so now Carl takes 1/6 from that 2/3
the answer isn't 13/18 13/18 is how much Al + Bert + Carl took how much is left over aka unclaimed is 1 - 13/18
5/18 is the answer so let me try to explain lets say its a pie albert eats 1/2 of the pie the bert eats 1/3 of a half which is 1/6 meaning there is 1-1/2-1/6=2/6 of pie left and carl eats 1/6 of 1/3(2/6 simplified) did i explain it correctly?
yup!
ok thx
you're welcome
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