Question

ss below

Answer 1

@florisalreadytaken

Answer 2

the same question?

Answer 3

no

Answer 4

the formula of the circle is \( (x-a)^2 + (y-b)^2 = c^2 \) remember?

firstly lets find the distance from the center of the circle, to a point of it

we know that \( (x,y ) = (0,0)\) and \( (a,b)=(0,6) \)

we can write that \( r=\sqrt{x-a)^2+(y-b)^2} \)

plug the numbers in*

Answer 5

x-0^2+y-6^2

Answer 6

no -- look carefully

it would be like this:
\[ r=\sqrt{(0-0)^2+(0-6)^2} \]

Answer 7

ohhh ok

Answer 8

r=6

Answer 9

correct!

so we have
\[(0-0)^2 + (0-6)^2 = 6^2\]

Answer 10

yup is that the answer?

Answer 11

no.

Answer 12

ha lol

Answer 13

i didnt think so lol

Answer 14

i didnt notice

there in the end is not an exponential 2 sign

the CORRECT answer would be:
\[ (0-0)^2 + (0-6)^2 = 6^2
\Rightarrow (0-0)^2 +
(0-6)^2 = 36 \]

Answer 15

oh ok