Just check my work for the problem below. my work is in the comments. (refrain from answering until it's up)
problem:
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit.

x2 + 4x + y2 − 6y = −4

Question

Just check my work for the problem below. my work is in the comments. (refrain from answering until it's up)
problem: 
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit.

x2 + 4x + y2 − 6y = −4

Honda · Answer

x^2+4x+y^2-6y=-4
(x^2+4x)+(y^2-6y)=-4
(4/2)^2=4
(6/2)^2=9
(x^2+4x+4)+(y^2-6y+9)=-4+(4+9)
(x^2+4x+4)+(y^2-6y+9)=9
(x+2)^2+(y-3)^2=3^2
center=(-2.3) Radius=3

Katrin369 · Answer

@honda wrote:

x^2+4x+y^2-6y=-4 (x^2+4x)+(y^2-6y)=-4 (4/2)^2=4 (6/2)^2=9 (x^2+4x+4)+(y^2-6y+9)=-4+(4+9) (x^2+4x+4)+(y^2-6y+9)=9 (x+2)^2+(y-3)^2=3^2 center=(-2.3) Radius=3

You should be good :)

200082741 · Answer

@katrin369 You sure it's not 6..?

Katrin369 · Answer

Yes I'm sure.

200082741 · Answer

@honda put in 3 but if it's wrong try 6

Honda · Answer

@200082741 wrote:

@honda put in 3 but if it's wrong try 6

I only have one chance to get this right.

Katrin369 · Answer

Try 3.

200082741 · Answer

Oh shoot nvm- yeah it's 3

200082741 · Answer

I was solving for x xD mb

Honda · Answer

alright. thanks guys