Using the following equation, find the center and radius: x2 + 2x + y2 + 4y = 20 The center is located at (1, 2), and the radius is 25. The center is located at (−1, 2), and the radius is 25. The center is located at (−1, −2), and the radius is 5. The center is located at (1, 2), and the radius is 5.
Look at the equation and, Convert it to the sum of two squares by using a simple method After doing that you'll get the equation \[(x+1)2+(y+2)2=25\] Next Look up the formula for a circle with a center that is not at ( 0,0 ) in standard form The rest should come easy
Hmmm idk
Formula: \(\bf{(x-h)^{2} + (y-k)^{2}=r^{2}}\) `(h,k)` is your center `r` is your radius @xxemilianaxx provided with your equation already, you should come by the answer quite easily with the explanation and provided formula.
So the answer would be " The center is located at (−1, 2), and the radius is 25. which is option B.)
Your total is `25` not `25^2` you need to find `r`. To do this you need to find the square root of `25`. Also, `x` is correct as `-1` but keep in mind if you have `y-k` and your equation is `y+2` then that means that `2` is `-2`
Hmmmm is it would be " The center is located at (−1, −2), and the radius is 5."
Correct!
That's correct
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