Question

help please(ss below)

Answer 1

Firstly, do you know that Pythagorean's theorem states?

Answer 2

no

Answer 3

Pythagorean's Theorem states A^2 + B^2 = C^2

Answer 4

So using the info from the problem, how do you think the data would go into the theorem?

Answer 5

so i do 8^2 for A,B?

Answer 6

Not quite
A^2 is one leg of the triangle
B^2 is the other leg
C^2 is the hypotenuse

Answer 7

ya lost me

Answer 8

The hypotenuse is always the measurement across from the right angle

Answer 9

so wouldnt A be 8

Answer 10

so 8^2

Answer 11

which would be 64

Answer 12

Yep

Answer 13

so then B is 8^2 too?

Answer 14

Yep, you can use either A or B for the other 8^2

Answer 15

and then its 64 + 64 then =?^2?

Answer 16

Yep, what do you think is after that?

Answer 17

64+64=128^2=16384

Answer 18

I would squareroot the 128
try that and see what it gets you

Answer 19

11.313708499

Answer 20

so 11?

Answer 21

Yep, sorry if it was confusing in a way...it's been kind of a while since I did this myself but I understand how to do it

Answer 22

so the answers 11?

Answer 23

it just said that 11 is incorrect

Answer 24

Hmm.... @snowflake0531 can you give some assistance please?

Answer 25

what the *censored word* are you guys doing ._.

Answer 26

i honestly have no damn idea xd

Answer 27

the purple triangle

Answer 28

Can you tell me the length of A an C?

Answer 29

so A is 8 and B is 0?

Answer 30

A would be 8 and so would be C

Answer 31

4

Answer 32

Yes so \[b^2 + 4^2=8^2 \]

Answer 33

so its 16=64?

Answer 34

\[b^2+16=64\\b^2=48\\b=\sqrt{48}\]

Answer 35

so i'd subtract 16 from 64 to get the answer?

Answer 36

i gave you the answer but yes

Answer 37

ik i meant thats how i would get the answer to these is subtracting wut A and B equal to C

Answer 38

?

Answer 39

do you know how to solve for a variable in a regular equation?

Answer 40

hold up ima post the next one to make sure im doing this right