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Mathematics 9 Online
hamidiso23:

x = ?? degrees

hamidiso23:

1 attachment
hamidiso23:

where would we start

jhonyy9:

arc BD = ? is the question ?

hamidiso23:

the question is find x

hamidiso23:

in degrees

jhonyy9:

i think you can use this : The Outside Angles Theorem states that the measure of an angle formed by two secants, two tangents, or a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs.

Florisalreadytaken:

yes, circle theorems \[ m \angle C = \frac{1}{2}(\overset{\Large\frown}{PE} -\overset{\Large\frown}{x} ) \] \[ 48 = \frac{1}{2}(\overset{\Large\frown}{140} -\overset{\Large\frown}{x} ) \] \[ 48=70+ \frac{-1}{2}x \] \[ 48 -70=\frac{-1}{2}x \] \[ -22=\frac{-1}{2}x \] \[ \frac{2}{-1}( -22)=x \] \[ 44=x \]

hamidiso23:

@florisalreadytaken wrote:
yes, circle theorems \[ m \angle C = \frac{1}{2}(\overset{\Large\frown}{PE} -\overset{\Large\frown}{x} ) \] \[ 48 = \frac{1}{2}(\overset{\Large\frown}{140} -\overset{\Large\frown}{x} ) \] \[ 48=70+ \frac{-1}{2}x \] \[ 48 -70=\frac{-1}{2}x \] \[ -22=\frac{-1}{2}x \] \[ \frac{2}{-1}( -22)=x \] \[ 44=x \]
100% sure its right

Florisalreadytaken:

why ask -- is there any possible reason for you to say that its wrong?

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