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x = ?? degrees
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where would we start
arc BD = ? is the question ?
the question is find x
in degrees
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i think you can use this : The Outside Angles Theorem states that the measure of an angle formed by two secants, two tangents, or a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs.
yes, circle theorems \[ m \angle C = \frac{1}{2}(\overset{\Large\frown}{PE} -\overset{\Large\frown}{x} ) \] \[ 48 = \frac{1}{2}(\overset{\Large\frown}{140} -\overset{\Large\frown}{x} ) \] \[ 48=70+ \frac{-1}{2}x \] \[ 48 -70=\frac{-1}{2}x \] \[ -22=\frac{-1}{2}x \] \[ \frac{2}{-1}( -22)=x \] \[ 44=x \]
@florisalreadytaken wrote:
yes, circle theorems
\[ m \angle C = \frac{1}{2}(\overset{\Large\frown}{PE} -\overset{\Large\frown}{x} ) \]
\[ 48 = \frac{1}{2}(\overset{\Large\frown}{140} -\overset{\Large\frown}{x} ) \]
\[ 48=70+ \frac{-1}{2}x \]
\[ 48 -70=\frac{-1}{2}x \]
\[ -22=\frac{-1}{2}x \]
\[ \frac{2}{-1}( -22)=x \]
\[ 44=x \]
why ask -- is there any possible reason for you to say that its wrong?
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