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Mathematics 17 Online
hamidiso23:

Find the length of Angle AB. Round to nearest tenth

hamidiso23:

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hamidiso23:

@snowflake0531

Timmyspu:

Ok. so what is the first thing we need to do to try to solve this?

hamidiso23:

Centeral angle /360° = AB length/2 pi r

snowflake0531:

Arc length formula \(2\pi r(\frac{\theta}{360}\)) where r is radius and theta is your angle

snowflake0531:

So it's \(2(\pi)(4)(80)/360\)

hamidiso23:

AB= 5.582

hamidiso23:

5.6?

snowflake0531:

yes

hamidiso23:

1 attachment
hamidiso23:

heres another one

snowflake0531:

Use the formula

hamidiso23:

Arc length formula 2πr(θ360)

Timmyspu:

@snowflake0531 wrote:
Arc length formula \(2\pi r(\frac{\theta}{360}\)) where r is radius and theta is your angle
There is the formula

hamidiso23:

so we do 2 times pie?

snowflake0531:

\[2\pi(8)(225)/360\]

hamidiso23:

2 times pie right?

snowflake0531:

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hamidiso23:

31.4 is the answer

hamidiso23:

in nearest tenth?

snowflake0531:

yes

snowflake0531:

and if you're about to post another new question new post please

hamidiso23:

ok thank you snow

snowflake0531:

yw~

hamidiso23:

r u sure

hamidiso23:

its 31.4

hamidiso23:

wouldnt it be this

hamidiso23:

the area of sector = 225/360×3.14×8² = ⅝ × 3.14 × 64 = 3.14 × 40 = 125.6 cm²

snowflake0531:

no lol, it's 2pi r, not pi r^2

hamidiso23:

u calaculated

hamidiso23:

for length of arc not for sector

snowflake0531:

damn true didn't read the question o-0

hamidiso23:

lol

snowflake0531:

then yeah you're correct lol

hamidiso23:

so 125.6

hamidiso23:

would that be nearest tenth

snowflake0531:

no you have 125.66

hamidiso23:

what would the answer be

hamidiso23:

in nearest tenth

snowflake0531:

round up

hamidiso23:

125.6

snowflake0531:

... if it was 125.6 i wouldn't have said 'no'

hamidiso23:

125.7

snowflake0531:

Use pi, not 3.14 o-0

1 attachment
snowflake0531:

@hamidiso23 wrote:
125.7
yes

hamidiso23:

tnx

snowflake0531:

yw~

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