Mathematics
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hamidiso23:
Find the length of Angle AB. Round to nearest tenth
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hamidiso23:
hamidiso23:
@snowflake0531
Timmyspu:
Ok. so what is the first thing we need to do to try to solve this?
hamidiso23:
Centeral angle /360° = AB length/2 pi r
snowflake0531:
Arc length formula \(2\pi r(\frac{\theta}{360}\))
where r is radius and theta is your angle
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snowflake0531:
So it's \(2(\pi)(4)(80)/360\)
hamidiso23:
AB= 5.582
hamidiso23:
5.6?
snowflake0531:
yes
hamidiso23:
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hamidiso23:
heres another one
snowflake0531:
Use the formula
hamidiso23:
Arc length formula 2πr(θ360)
Timmyspu:
@snowflake0531 wrote:
Arc length formula \(2\pi r(\frac{\theta}{360}\))
where r is radius and theta is your angle
There is the formula
hamidiso23:
so we do 2 times pie?
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snowflake0531:
\[2\pi(8)(225)/360\]
hamidiso23:
2 times pie right?
snowflake0531:
hamidiso23:
31.4 is the answer
hamidiso23:
in nearest tenth?
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snowflake0531:
yes
snowflake0531:
and if you're about to post another
new question new post please
hamidiso23:
ok thank you snow
snowflake0531:
yw~
hamidiso23:
r u sure
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hamidiso23:
its 31.4
hamidiso23:
wouldnt it be this
hamidiso23:
the area of sector = 225/360×3.14×8²
= ⅝ × 3.14 × 64
= 3.14 × 40
= 125.6 cm²
snowflake0531:
no lol, it's 2pi r, not pi r^2
hamidiso23:
u calaculated
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hamidiso23:
for length of arc not for sector
snowflake0531:
damn true didn't read the question o-0
hamidiso23:
lol
snowflake0531:
then yeah you're correct lol
hamidiso23:
so 125.6
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hamidiso23:
would that be nearest tenth
snowflake0531:
no you have 125.66
hamidiso23:
what would the answer be
hamidiso23:
in nearest tenth
snowflake0531:
round up
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hamidiso23:
125.6
snowflake0531:
... if it was 125.6 i wouldn't have said 'no'
hamidiso23:
125.7
snowflake0531:
Use pi, not 3.14 o-0
snowflake0531:
yes
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hamidiso23:
tnx
snowflake0531:
yw~