The perimeter of Dana's rectangular garden is 61 feet. The length of her garden is 5 feet more than twice the width. The perimeter of a rectangle can be found by adding the lengths of its four sides

Question

The perimeter of Dana's rectangular garden is 61 feet.  The length of her garden is 5 feet more than twice the width. The perimeter of a rectangle can be found by adding the lengths of its four sides

mhanifa · Answer

Do you know the perimeter formula?

Extrinix · Answer

$61=(2(w)+5)+(2(w)+5)+w+w$
So simplified would be:
$61=6w+10$
Now solve for the width,
$61=6w+10$
$51=6w$
$8.5=w$
Plug it in:
$61=(2(8.5)+5)+(2(8.5)+5)+8.5+8.5$
Which we can simplify into $P=2l+2w$
$61=2(22)+2(8.5)$

So, from this we get our length and width,
$l = 22$
$w = 8.5$