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Mathematics 17 Online
kaydademon:

ss below

kaydademon:

1 attachment
kaydademon:

@xxemilianaxx @florisalreadytaken @smokeybrown

xxemilianaxx:

To rewrite it in the standard form a + bi, You need to multiply the numerator and denominator by the conjugate 3 + 1i

xxemilianaxx:

Wait mb 2i*

xxemilianaxx:

So what would the equation be?

kaydademon:

(8−i / 3−2i) ( 3+2i / 3+2i) = 24+16i−3+(−i)(2i) / (3^2)−(2i)^2

xxemilianaxx:

Since i2=−1 the fraction can be reduced simplified to?

kaydademon:

would it be cheating if i use a calculator

xxemilianaxx:

Lol no

kaydademon:

24+16i−3i+2 / 9−(−4) = 26+13i / 13

xxemilianaxx:

That simplifies further to 2+i. Thus, when 8−i / 3−2i is written in the standard form a + bi the value of a would be 2

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