Question

A line has a SLOPE = -4 and passes through the POINT (8, -3). Write the equation of the line in slope-intercept form.

Answer 1

whats the question tho-?

Answer 2

that is the question

Answer 3

do you know the equation form

Answer 4

The slope of the line is -4, which means that (assuming we are using x-y coordinates as usual), every time x increases by 1, y decreases by 4.
We also know that (8, -3) is a point on the line. Knowing the slope, we can work backwards to find the y-intercept (which is the value of y when x is 0).
So, if y is -3 when x is 8, y would be (-3 - (8*(-4))) = -3 + 32 = 29 when x is 0.
So, now we know the slope (-4) and the y-intercept (29)
Can you figure out how to put this information together to write the equation of the line in slope-intercept form?

Answer 5

eq. of line in slope intercept form is y=mx+c
Here m=-4
so eq. of line is y=-4x+c
\[\because ~it~passe~through~(8,-3)\]
so -3=-4(8)+c
c=-3+32=29
Hence eq. of line is y=-4x+29