help plzz
Solve the following linear equation for x and y via substitution y=x+1 2y+3x = 22 x = 4, y = 5 x = 4, y = 5 x = -1, y = 6 x = -1, y = 6 x = 3, y = 7 x = 3, y = 7 y = 4, x = 2
with this
yesh
@smokeybrown
oki gimmie 3 mins
ok thx
do you know how the first step in solving this problem?
noooo tbh its suposed to be review but idk anything of this type of math plus e has not showed us how to
hmm. Well substitution is a process in math where you input one equation in the set into the other equation
here it says that y = x + 1. So to do substitution we must replace all y values in the second equation (2y+3x = 22) with x+1
y=x+1 2y+3x = 22 The question prompts you to use "substitution" to solve the system of equations. To begin with, you can substitute "y" for "x + 1" in the second equation; this is because the first equation tells you that "y=x+1" As a result of this substitution, you get: 2(x+1) + 3x = 22 From there, you may simplify in order to solve for the value of x. Once you solve for x, you may use substitution with the value of x you found in order to find the value of y. In the end, you will have found the values of both x and y to satisfy the system of equations. Please, go ahead and solve for x using the substitution demonstrated above. If you need more help after that, we may continue from there
oooooooooo thank yall soo much
well, smokey brown I suppose did a better job explaining, but I prefer to do a hands on approach. Either way smokey is correct.
lol thank yall
of course.
ughh brb we got to go to dif classes thank yall
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