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Chemistry help please
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@vocaloid
You're given two positive ions and two negative ions Generally, an ionic compound is made from one positive and one negative ion So, you have 4 combinations to consider. Write the positive ion, then the negative ion. You also need to balance out charges. I'll demonstrate using one possible combination. Pb4+ , and ClO3- The Pb4+ has a +4 charge, and the ClO3- has a -1 charge So we need 4 ClO3- ions to balance out the +4 charge. We represent this by putting a set of parentheses around ClO3-, and adding a 4 subscript. So finally: \[Pb(ClO_{3})_{4}\] is your ionic compound. Notice since, the overall compound is neutral, we don't write the charges. Try to repeat with the other 3 options.
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