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3(2x-2)=2(x+3)
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Were trying to solve for x is that correct?
@itsmehjay wrote:
Were trying to solve for x is that correct?
Alrighty! So first things first we need to distribute the 3 and the 2 to every term inside the parenthesis
@itsmehjay wrote:
Alrighty!
So first things first we need to distribute the 3 and the 2 to every term inside the parenthesis
No, if were distributing, were multiplying the number outside the parenthesis to every term inside it
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So the equation says 3(2x-2) Your going to be multiplying 3 to 2x and -2
So same thing with 2(x+3) Multiply 2 by x and 3
So what would you get for the first set?
You should've gotten 6x-6=2x+6 Now try solving for x
k
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