Question

Consider the following relation.

5x−2y=3x−6y

Evaluate the function found in the previous step at x = -2.

f(-2) =

Answer 1

@tranquility

Answer 2

What was the function found in the previous step?

Answer 3

the previous step answer was \[f(x) = \frac{ -x }{ 2 }\]

Answer 4

To evaluate the function at x = -2, you simply replace x with -2 and simplify

What is -2/2 = ?

Answer 5

-1

Answer 6

That is your final answer

(assuming the function you provided is correct from the previous question)

Answer 7

it was 1

Answer 8

oh, I completely missed that negative sign

I'm sorry

Answer 9

-(-2)/2 = 1

Answer 10

yes

Answer 11

i have another one

Answer 12

Sure

Answer 13

Consider the following relation.

\[-2y + \sqrt[3]{x} = -2x + x^{2}\]

Evaluate the function found in the previous step at x=−1.

f(-1) =

Answer 14

this is the step answer from the previous question if you wonder and look closely

Answer 15

@minustempo

Answer 16

@tranquility

Answer 17

replace x with -1

\(\dfrac{\sqrt[3]{-1} -(-1)^2 + 2(-1)}{2}\)

If you don't know, \(\sqrt[3]{-1} = -1\)