Question

Find the axis of semmetry for this parabola: y=-5x^2-10x-13
Write your answer as an equation.

Answer 1

@extrinix

Answer 2

So the formula for the axis of symmetry is \(x=-\dfrac{b}{2a}\)

Plug in your equation's values of \(y=ax^2+bx+c\)
\(y=-5x^2-10x-13\)

\(x=-\dfrac{-10}{2(-5)}\)

So what would you get?

Answer 3

1

Answer 4

Correct, so that would be your axis of symmetry

Answer 5

so x=1

Answer 6

Yeah

Answer 7

Then if you're trying to find the vertex, plug in your answer for \(x\) into the equation and solve for \(y\), that would be your \((x,y)\)