can someone help me with changing this logarithmic expression to exponential?
\[\log_{3}(1/81)=-4\]
my prof told us the answer is x < 2 ????
\[\log_{a}b=y \]
is equal to
\[\log_{a} b = x\] is the same as \[a^x=b\]
\[a^y=b\]
So knowing this, can you try and create it into a correct form?
3^-4=1/81, but how would that equal x<2 ?
there's no "x" in the question 3^-4 = 1/81 is correct
When a negative is in the exponent, the number becomes a fraction.
is my prof just tripping then
unless there's another part to your question
yes
ok good i was going bonkers ...
no he literally gets so many questions wrong ... actually attending the lectures confuses me more than not going and figuring it out on my own
thank you guys
you're doing this in college?..
yes its just a basic entry level math course required for my degree plan
plus it might be nice to add that because of the pandemic i missed about two years of math education ... i am very lost
ah
You didn't need to come judgemental. Everybody coems from different mathematical backgrounds. You're on the right track @lolokrat
no worries i took no offense lol i just need the credit and ill never have to do this math again ... QC has been helping me a lot in figuring this stuff out though
Oh that's great, everyone loves helping. Wish you luck!
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