Vitellium (Vi) has the following composition:
Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%

Based on this data, what can you predict about the average atomic mass of vitellium?

A. It will be equal to the arithmetic mean of the masses of the three isotopes.
B. It will be closer to the mass of Vi–188.
C. It will be closer to the mass of Vi–193.
D. It will be equal to the mass of Vi–193.

Question

Vitellium (Vi) has the following composition:
Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%

Based on this data, what can you predict about the average atomic mass of vitellium?

A. It will be equal to the arithmetic mean of the masses of the three isotopes.
B. It will be closer to the mass of Vi–188.
C. It will be closer to the mass of Vi–193.
D. It will be equal to the mass of Vi–193.

minustempo · Answer

you calculate average atomic mass by doing (percent mass1 * mass1) + (percent mass2 * mass2) + (percent mass3 * mass3) etc
So the average atomic mass here would be
187.9122*0.10861 + 190.9047*0.12428 + 192.8938*0.76711

lifewmylilweeb · Answer

@minustempo wrote:

you calculate average atomic mass by doing (percent mass1 * mass1) + (percent mass2 * mass2) + (percent mass3 * mass3) etc So the average atomic mass here would be 187.9122*0.10861 + 190.9047*0.12428 + 192.8938*0.76711

thank you i know the answer now

minustempo · Answer

you're welcome