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Mathematics 11 Online
makaylab:

HELP I'LL GIVE MEDAL!

makaylab:

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makaylab:

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makaylab:

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makaylab:

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MidniteSunny:

dang oki gotta break out my old binder for this oki so the first one is by graphing, so 1) solve each equation for y

MidniteSunny:

do yk how to do that ?

MidniteSunny:

well in any case, at least in the frst problem u dont hav to 2) Graph both lines on the same coordinate plane

makaylab:

@midnitesunny wrote:
do yk how to do that ?
no

MidniteSunny:

to graph y = -x + 1, u use the slope and y-intercept, in this case the slope is -1 and the y-intercept is (0, 1)

MidniteSunny:

u can plot those points and draw a line through them

makaylab:

so would it be y=mx+b?

MidniteSunny:

that is what the question's form is rn yesh

MidniteSunny:

where b is the y-intercept and m is the slope

makaylab:

ok

MidniteSunny:

it should look sumthing like this

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MidniteSunny:

for the other equation, y = -1/4x - 2, it's the same case, u graph it as well

makaylab:

ok but how...

MidniteSunny:

by using the slope and y intercept, remember the equation is in y=mx+b form, where m is the slope and b is the y intercept

MidniteSunny:

plot the y intercept point, which would b (0, -2)

MidniteSunny:

and w/ the case of a negative fraction as ur slope, u simply go down however much the numerator (top number) is, and then to the right however much the denominator is

makaylab:

@midnitesunny wrote:
and w/ the case of a negative fraction as ur slope, u simply go down however much the numerator (top number) is, and then to the right however much the denominator is
would the points be(-8,-2)?

MidniteSunny:

not quite, instead the points to put a line through r (0, -2), and (4, -3)

makaylab:

@midnitesunny wrote:
not quite, instead the points to put a line through r (0, -2), and (4, -3)
ohhhhh ok

MidniteSunny:

mhm ^^ so next, once u hav graphed those, would b 3) determine the solution from the graph the solution is the point where those two lines intersect

MidniteSunny:

@makaylab tell me when chu think ya got it ^^

makaylab:

@midnitesunny ok!

MidniteSunny:

ish been awhile so imma say the steps to figure out #2 just in case, 1) solve the equation for y if u need to (which u dont) 2) graph both lines on the same coordinate plane (using the slope and y-intercept from the equations) 3) determine the solution from the graph (the point of intersection between both lines)

makaylab:

ok i got it i just need the others now T-T

MidniteSunny:

chu got #1 and #2 ? or just #1

makaylab:

1

MidniteSunny:

oki so #2 we will refer bacc to ze steps ive previously mentioned

MidniteSunny:

we skip the first step and so now we graph ze first of them equations

MidniteSunny:

y = 3/5x + 8, where 3/5 ish the slope and 8 represents the y-intercept [ (0, 8) ]

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