Question

Solve the system by substitution:
3x + 2y = 8
x = 4 - 2y

Answer 1

Substitute the second equation into the first one

3x + 2y = 8
x = 4 - 2y

The second equation is x equals 4 - 2y
So to solve it, replace 'x' in the first equation with 4 - 2y

You then get

3(4-2y) + 2y = 8

Now you have an equation with just one variable which is y and you can find out the value of y.

Can you simplify that equation and solve for y?

First distribute the 3 inside the parenthesis

3(4-2y) + 2y = 8

Answer 2

12-6y+2y=8
12-4y=8

Answer 3

Solve for y. Get y all by itself one side

Answer 4

12 - 4y = 8

You can 4y on both sides and then subtract 8 on both sides

Answer 5

alright

Answer 6

x = 4 -2y

We found out y = 1

Replace y with 1 and solve for x

x = 4 - 2*(1)

Answer 7

4=-2y
0.5

Answer 8

... no

Answer 9

3x - 2y = 8
3x-2(1)=8
3x-2=8
3x=10
3.33

Answer 10

You wrote the equation incorrectly.

It's 3x PLUS 2y = 8

Not 3x minus 2y = 8

Answer 11

3x + 2y = 8
3x+2(1)=8
3x+2=8
3x=6
x=2

Answer 12

Do you still need help with this?