I believe for the first part it would be -5 and something
Hmmmm ok thanks
lifewmylilweeb:
@joe348 wrote:
I believe for the first part it would be -5 and something
yeah there is (-5,0), (-1,0), (4,0), and (7,0)
kekeman:
Thanks
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lifewmylilweeb:
yw
lea0728:
@lazorwolf64
kekeman:
@lifewmylilweeb wrote:
@joe348 wrote:
I believe for the first part it would be -5 and something
yeah there is (-5,0), (-1,0), (4,0), and (7,0)
Wait there is no -2?
SmokeyBrown:
@kekeman wrote:
Wait there is no -2?
When x = -2, y is around 4, not 0, so -2 would not be a zero of the curve
kekeman:
Ohhhh ok thanks
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kekeman:
I just need to figure out what to come up with on part B.)
SmokeyBrown:
For part 2 of the question, you don't need to give the actual equation of the curve, just a possible equation based on the zeroes you found in part 1. (By the way, I think -5 and 4 are the ones with "possible multiplicities", since the shapes when they intersect are a parabola and a cubed function, respectively. I could be off base with this conclusion)
So, with the zeroes -5, -1, 4, 7, assuming -5 has multiplicity of 2 and 4 has multiplicity of 3, one possible equation could be:
(x+5) * (x+5) * (x+1) * (x-4) * (x-4) * (x-4) * (x-7)
This would also result in a seventh-degree polynomial, as the problem describes since 7 terms are multiplied together.
I think this is what the question is getting at, but to be honest, I'm guessing a bit on some parts
kekeman:
@smokeybrown wrote:
For part 2 of the question, you don't need to give the actual equation of the curve, just a possible equation based on the zeroes you found in part 1. (By the way, I think -5 and 4 are the ones with "possible multiplicities", since the shapes when they intersect are a parabola and a cubed function, respectively. I could be off base with this conclusion)
So, with the zeroes -5, -1, 4, 7, assuming -5 has multiplicity of 2 and 4 has multiplicity of 3, one possible equation could be:
(x+5) * (x+5) * (x+1) * (x-4) * (x-4) * (x-4) * (x-7)
This would also result in a seventh-degree polynomial, as the problem describes since 7 terms are multiplied together.
I think this is what the question is getting at, but to be honest, I'm guessing a bit on some parts
Polynomial's zeroes: -5, -1, 4, 7
Possible multiplicities: x = 7 (multiplicity of 1), x = 4 (multiplicity of 1), x = -1 (multiplicity of 1), x = -5 (multiplicity of 2).
Is this right?
SmokeyBrown:
I think 4 has a multiplicity of 3, based on the shape of the curve near that point, but I could be mistaken about that
kekeman:
Omg yes thats what i was thinking
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kekeman:
So 4 has a multiplicity of
kekeman:
3
kekeman:
Which one would be a better one for part B.) (x+5)^2(x+1)(x+2)(x-4)(x-7) or -(x-4)^3*(x+5)^2*(x+1)*(x-7)
SmokeyBrown:
Sorry for the late response
I think I would go with the second option, -(x-4)^3*(x+5)^2*(x+1)*(x-7)
The formatting is a bit neater and it shows the proper multiplicity of 4 and -5
kekeman:
Ok even putting "*" in between it?
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SmokeyBrown:
Yeah, you can use the asterisk * to signify multiplication so that's fine to include