Question

Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work for full credit

Answer 1

' y=(-5/12)x+8 '

find y=mx+b for line parallel to AB. the slope of line AB is m=(8-3)/(-10-2)
=5/-12
=-5/12

Answer 2

i believe you would get y=(-5/12)x+8 as your answer

Answer 3

wow you are good at math angle

Answer 4

I'm not good at math at all lol

Answer 5

respectfully disagree with previous answer

first, the equation of AB
the slope is -5/12
to find the y -intercept, take the slope and one coordinate (2,3)
3 = -5/12 (2) + b
3 = -5/6 + b
b = 3 5/6
so the equation of AB is \(y=−\frac{5}{12}x+3\frac{5}{6}\)

Now, we have to find the line perpendicular, that goes through (-5,10)
let's first find the slope
the perpendicular line's slope is always negative reciprocal, so the slope would be 12/5
now, we use the slope and coordinate to find the y intercept
10 = 12/5 (-5) + b
10 = -12 + b
b = 22

so the perpendicular line is \(y=\frac{12}{5}x+22\)

Answer 6

@snowflake0531 u saved me thx

Answer 7

yw~