A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have?

Which of the following equations could be used to solve the problem?

x + (11 - x) = 1.70
0.10x + 0.25(11 - x) = 1.70
25x + 10(11 - x) = 1.70

Question

A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have?

Which of the following equations could be used to solve the problem?

x + (11 - x) = 1.70
0.10x + 0.25(11 - x) = 1.70
25x + 10(11 - x) = 1.70

Vocaloid · Answer

Let’s try defining x as the number of dimes

The value of 1 dime is 0.10 dollars
Therefore, the value of x dimes is 0.10x

If there are 11 total coins then 11 - x is the number of quarters. If 1 quarter is 0.25 dollars then how much money is (11-x) quarters worth?

Once you determine both the dime and quarter values, sum them and set it equal to the total value 1.70

aboyles · Answer

oh thank you for you help