Question

The following reaction shows sodium hydroxide reacting with sulfuric acid.

4NaOH + 2H2SO4 → 2Na2SO4 + 4H2O

How many grams of Na2SO4 are produced from 10.0 grams of NaOH?

(Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.065 g/mol)

17.8 grams
19.2 grams
35.5 grams
38.5 grams

Answer 1

17.8 grams ?

Answer 2

U sure

Answer 3

@cutebunny123

Answer 4

yup, do you want the working ?

Answer 5

Yes pls

Answer 6

okay so first of all , find the moles of NAOH by using 10 grams and 39.996 as its mr and youll get 0.2500 mol. Now the mol ratio between NAOH and NA2SO4 is 4 : 2 as given in the equation in the question. we found the moles for NAOH which was 0.2500 so now you can cross multiply and get the moles for NA2SO4 ( 0.2500 x 2 / 4 = 0.125 ). Now the moles for NA2SO4 are 0.125 and its mr is 142.039 ( calculated using the masses above ) and you can multiply them to get the mass using the moles = mass / mr equation. Hope this helps !

Answer 7

So we get 17.8 grams

Answer 8

yes

Answer 9

thanks