When a new cellphone is put on the market, the demand each month can be described by the function C of t is equal to negative square root of the quantity t squared minus 4 times t minus 12 end quantity plus 3 where C (t) represents the demand of the cellphone (measured in millions of people) and the time, t, is measured in months. Which of the following solution(s) are valid for a positive demand? (2, 3) (6, 3) (3, 0) and (7, 0) (–2, 3) and (6, 3)
\[C(t) = - \sqrt{(t^{2}-4t-12)} +3 \] (2, 3) (6, 3) (3, 0) and (7, 0) (–2, 3) and (6, 3) - so just substitute these given roots inside given expression and check what will satisfy the equality - in place of x is t and in place of y is C(t) for example (2,3) C(2) = 3 check please this ,substitute in place of t the 2 and you need get 3 for right result hope helped understandably easy
Hmmm okay so I have do to this for every option or are u saying it is (2,3)
Sorry this cal is super confusing to me
Hey I put in in desmos on the graphing thing and I am pretty sure it is (6,3)
You helped a lot love ya!
np anytime
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