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Rewrite 1/12x^3y + 7/12xy^2 using a common factor. 1/6xy(x^2 + 7y) 1/6xy(2x^2 + 7y) 1/12xy(x^2 + 7y) 1/12x^3y^2(y + 7x)
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\[1/12x ^{3}y+7/12xy ^{2}\]
is that what it looks like on ur end?
Ooou jules is a math whiz.
@jkmiec26 wrote:
@vlore wrote:
Ooou jules is a math whiz.
\[1/12xy(x ^{2}+7y)\] Would be ur answer.
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Because when you take out the common factor of 1/12xy. It comes out of the whole problem so you're only left with x^2 and 7y.
Ok
Thanks
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