Question

given the balanced equation:2H2+CO>CH3OH, how many moles of CH3OH will be produced if 12.6g H2 reacts with 114.5 g CO?

Answer 1

The equation is already balanced so you can go straight to the stoichiometry.

Determine your limiting reactant first by converting 12.6g H2 and 114.5g CO2 to moles by dividing by their respective molar masses. Then use the reaction coefficients to convert both reactants to moles CH3OH and see which one makes less product, that’ll be your limiting reactant.

Finally, from there, continue from your limiting reactant, convert the moles of CH3OH produced by the LR into grams by multiplying by the molar maaa of CH3OH.

Answer 2

what is the answer

Answer 3

Please keep in mind the purpose of this site is to teach rather than give away answers.

Can you try the conversions? Divide 12.6 g H2 by the molar mass of H2 (2.016g/mol)

Answer 4

yes

Answer 5

whats next

Answer 6

From there you’re now in moles H2. notice the balanced reaction coefficients 2 H2 to 1 CH3OH, meaning the reaction uses 2 mol H2 per 1 mol CH3. So you can divide moles H2 by 2 to get moles CH3OH.

Answer 7

i do not understand. I'm trying to teach my son and I'm totally lost. Can you please just help me with the answer.

Answer 8

We do not give away direct answers as per our rules: https://questioncove.com/rules

Answer 9

can you give me step by step to work it out myself

Answer 10

That's what I'm trying to do.

1. start with 12.6 g H2
2. divide by the molar mass of H2 to get moles
3. use the balanced equation to convert to moles CH3OH
4. repeat steps 1-3 with the other reactant CO2
5. see which reactant made less CH3OH. that's your limiting reactant.
6. using your limiting reactant, you already calculated how many moles CH3OH it made in a previous step. the question asks how many moles CH3OH your reaction made, so you would simply stop here and report how many moles CH3OH the limiting reactant made.

Answer 11

some terminology:
- a mole is 6.022 * 10^23 atoms/molecules/or formula units of a substance. in this case, we're working with molecules, so a mole would be 6.022 * 10^23 molecules.
- a molar mass is how much 1 mole of a substance weighs

to convert from mass to moles, we divide mass in grams by molar mass. so starting with H2, the molar mass of H2 is 2.016 g/mol (you can look these up on google or derive these by adding up the masses of the atoms on the periodic table.)

so to convert 12.6 g of H2 to moles, we simply divide 12.6 / 2.016 to get 6.25 moles H2

Answer 12

now, let's look at the reaction.

2H2 + CO --> CH3OH

This tells us 2 moles H2 makes 1 CH3OH. So to go from moles H2 to moles CH3OH we divide by 2. 6.25 moles H2 divided by 2 = 3.125 moles CH3OH. that's how many moles CH3OH we can make from 12.6 g H2.

repeat this process with CO * (I meant to say CO not CO2). the molar mass of CO is 28.01 g/mol.

Answer 13

would the answer be 3.125 or 4.09

Answer 14

so we've calculated that 12.6g H2 can make 3.125 moles product and 114.5g CO makes 4.09 moles product.

remember that the limiting reactant makes fewer moles of product.

3.125 moles is smaller than 4.09, so H2 is our limiting reactant and we only can make 3.125 moles CH3OH, which is your solution.

Answer 15

so i'm going to put the answer as 3.125

Answer 16

yes, 3.125 moles CH3OH

Answer 17

ok can you help me with another one

Answer 18

ok, I'll close this so you can make a new post

Answer 19

can i just tell it here

Answer 20

a chemistry mixes 108g of H2O with 186L if NO2 at STP. How many grams of NO will be produced

Answer 21

I meant NO2

Answer 22

Sorry how many grams of NO produced not NO2

Answer 23

NO2 + H2O--> HNO3 + NO

this reaction is unbalanced so we need to balance it (only 3 oxygen atoms on the left side, 4 on the right. 2 hydrogen atoms on the left side, 1 on the right. we double the HNO3 to get 2HNO3 to balance out the hydrogen atoms)

NO2 + H2O--> 2HNO3 + NO

now we have 7 oxygen atoms on the right side, so we can write a 3 in front of NO2 to get 3NO2 which brings the left side nitrogen total to 3. after this, everything is balanced.

final balanced equation: 3NO2 + H2O--> 2HNO3 + NO

Answer 24

like the previous problem we want to convert both substances to moles product. (in this case moles NO).

this is a gaseous reaction, so there's a special rule that applies here; 1 mole of any subtance takes up 22.4L of space. so to get from 186L NO2 to moles NO2, simply divide 186 L NO2 by 22.4L.

to convert 108g of H2O simply divide 108 by the molar mass of H2O (18.02 g/mol) to get moles H2O.

Answer 25

as before, the next step is to use the balanced reaction to convert to moles NO. whichever product gives you less NO is your limiting reactant. (you're looking for the *smaller* amount of NO made). from there, that amount of NO is how many moles you produced. since the question is asking for *Grams* NO you'll have to do one last step, multiply by the molar mass of NO.