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Using f(x) = log x, what is the x-intercept of g(x) = log (x + 4)?
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for f(x) = log(x), recall that log(1) = 0. therefore, the x-intercept is (1,0). recall function transformations. for horizontal transformations f(x+h), the function gets shifted to the left by x units. so applying this logic to our problem, the x-intercept of log gets shifted to the left 4 units.
Okay, that makes sense! That means I would do, 1 - 4 which is equal to -3. So the x-intercept is at (-3,0). Thank you so much! :)
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