Question

What is the simplified form of 6 log3x - 7 log3y + 4 log3z?

log base 3 of the quantity negative xz end quantity divided by 4y end log
log base 3 of 3xz divided by y end log
log base 3 of the quantity x to the sixth z to the fourth end quantity divided by y to the seventh end log
log base 3 of the quantity xy all raised to the twelfth end quantity divided by z to the 4th end log

Answer 1

The answer would be,
log base 3 of the quantity x to the seventh z to the fourth end quantity divided by y to the sixth end log

\[6\log _{3}x-7\log _{3}y+4\log _{3}z\]

You have to use the power law,
\[alog _{x}b=\log _{x}b ^{a}\]

so
\[\log _{3}x ^{6}-\log _{3}y ^{7}+\log _{3}z ^{4}\]

With all of this it shows it's the third option c:

Answer 2

I didn't realize how spaced out I put it whoops

Answer 3

Its perfectly fine.

Answer 4

i would say C

Answer 5

yeah thats what i said :0

Answer 6

yeah

Answer 7

wait u did