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iluvdogs:

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. What is the acceleration of the crate? (Hint: remember to find net force first) a= m/s2

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iluvhotmoms:

6.0 m/s2

TheKaylaHope:

Net force = Applied force - Force of friction Net force = 1860 N - 480 N Net force = 1380 N to the right

TheKaylaHope:

Net force = mass x acceleration We substitute the values: 1380 N = 230 kg x acceleration Solving for the acceleration: acceleration = 1380 N / 230 kg acceleration = 6 m/s^2 (rounded to the nearest whole number) Therefore, the acceleration of the crate is 6 m/s^2.

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