He would indeed be right on the answer, but here's how I was told to do it:
Given equation: \(x^3+9x^2+3x+27\)
Separate the equation into two:
\((x^3+9x^2)+(3x+27)\)
Factor each of these out:
\(x^2(x+9)+3(x+9)\)
Look for commons and cancel them out
\(x^2(x+9)+3\)
Combine the factored out values:
\((x^2+3)(x+9)\)
kacchanforlife:
ur right but just dont put the times sign
Darf87:
@kacchanforlife wrote:
ur right but just dont put the times sign
mhm thats what I meant
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Sharkattack123:
Alright thanks
kacchanforlife:
np!
ShoaibChaudhry:
Smh Shark so dum fr fr :>
Sharkattack123:
@shoaibchaudhry wrote:
Smh Shark so dum fr fr :>
Shut </3
ShoaibChaudhry:
@sharkattack123 wrote:
@shoaibchaudhry wrote:
Smh Shark so dum fr fr :>
Shut </3
Sorry bestie Anyways
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Extrinix:
You can test your answers by running a 1 as x through the problem
\((1)^3+9(1)^2+3(1)+27 = 40\)
\(((1)^2+3)((1)+9) = 40\)
Sharkattack123:
@extrinix wrote:
You can test your answers by running a 1 as x through the problem
\((1)^3+9(1)^2+3(1)+27 = 40\)
\(((1)^2+3)((1)+9) = 40\)