Question

2\5 help

Answer 1

i think it's b but i ain't sure

Answer 2

@OLIVER69 can you help?

Answer 3

You're close \(\downarrow\)

Probability:
\(probability = \dfrac{specific~ribbon}{total~ribbons}\)

So in this case, your probability is for the yellow ribbons, which is 12, and the total amount of ribbons is 22, so \(\dfrac{12}{22}\), which is \(\dfrac{6}{11}\)

Now, event probability goes by such:
\(0-33\%: unlikely\)
\(33-66\%: neither\)
\(66-100\%: likely\)

In this case, \(\dfrac{6}{11}\) is equal to \(0.\overline{54}\) which is \(54\%\).

Which is below 66%, making your event neither likely nor unlikely to occur.

Answer 4

Of course