What is the boiling point elevation when 40g of NaCl is added to 400 g of water?

Question

Vocaloid · Answer

$$\Delta T_b=i*m*K_{b}$$where delta Tb is the boiling point elevation, i is the van't hoff factor, m is the molality, and Kb is the boiling point constant.

NaCl dissociates into 2 particles, so i = 2
Kb is 0.512 for water
to calculate m, the molality, calculate (moles solute)/(kg solvent). your solute is NaCl, so convert 40g NaCl to grams by dividing by the molar mass. your solvent is water, so convert 400g to kg by dividing 400g/1000g/kg.

finally, once you have all three values, plug them into the formula and evaluate delta T.

zunairah · Answer

Is there an equation to find Kb? Or do I just have to search it up?

Vocaloid · Answer

Kb is a constant. for water it is 0.512.