Two separate rabbit populations are observed for 80 weeks, starting at the same time and with the same initial populations. The growth of two rabbit populations are modeled as follows, where t ! 0 corresponds to the beginning of the observation period: r1(t)=4sin((2pi/72)t)+0.1t+1, where r1 is rabbits per week, and t is time in weeks, r2(t)=t^(1/2), where r2 is rabbits per week and t is time in weeks.

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full question (please post this next time) https://media.cheggcdn.com/media%2F545%2F5457c874-a100-4888-b71c-e6e70732e3c2%2FphpsLwjBY.png A) to find the first positive point where the two graphs intersect, graph the two functions on a graphing calculator/graphing software and estimate where the first intersection point is. you can look up specific instructions based on the calculator you're using. visually, upon inspecting the graph, you can tell it's slightly above 30. B) because each graph represents the growth rate of each population, the area under the curve (the integral) represents the total population. therefore, the difference between the two curves is the difference between the two populations across that time period. C) as stated previously, the population of each rabbit population is represented by the integral of its growth rate, so integrate each function wrt t and set them equal to each other D) as stated, simplify the equation from part C) and use a calculator to calculate the exact value of T