Question

help plz

Answer 1

So we have to find the 30th percentile.
First we compute the population mean, which is 4,200 and the standard deviation which is 250.

z=(x-mean)/standard deviation
z=($3785.00-$4200.00)/$250.00

So the 30th percentile for the given distribution is $3,785.00

Answer 2

it said it was wrong :(

Answer 3

Aw, hm, I followed a yt tut so I'm not sure ;-; sorry ;-;