Question

What is the simplified product of z_(1) and z_(2) given that z_(1)=8+3i and z_(2)=1-4i?

differences too

Answer 1

U dont deserve help

Answer 2

but here
20-29i

Answer 3

And differences (i really do)

Answer 4

no more help for you bud

Answer 5

HELP NOW MEAN

Answer 6

To find the product of complex numbers
�
1
=
8
+
3
�
z
1
​
=8+3i and
�
2
=
1
−
4
�
z
2
​
=1−4i, you can use the distributive property of multiplication.

Let's calculate the product
�
1
⋅
�
2
z
1
​
⋅z
2
​
:

�
1
⋅
�
2
=
(
8
+
3
�
)
⋅
(
1
−
4
�
)
=
8
⋅
1
+
8
⋅
(
−
4
�
)
+
3
�
⋅
1
+
3
�
⋅
(
−
4
�
)
=
8
−
32
�
+
3
�
−
12
�
2
z
1
​
⋅z
2
​

​

=(8+3i)⋅(1−4i)
=8⋅1+8⋅(−4i)+3i⋅1+3i⋅(−4i)
=8−32i+3i−12i
2

​

Remember that
�
2
=
−
1
i
2
=−1, so you can substitute that in:

8
−
32
�
+
3
�
−
12
�
2
=
8
−
32
�
+
3
�
+
12
=
(
8
+
12
)
+
(
−
32
�
+
3
�
)
=
20
−
29
�
8−32i+3i−12i
2

​

=8−32i+3i+12
=(8+12)+(−32i+3i)
=20−29i
​

So, the product
�
1
⋅
�
2
z
1
​
⋅z
2
​
is
20
−
29
�
20−29i. The real part is 20, and the imaginary part is -29.

Answer 7

oopd

Answer 8

id find

Answer 9

???????????????????????

Answer 10

i solved it alreadyyyyy =(

Answer 11

real

Answer 12

z_1 \times z_2 = (8 + 3i) \times (1 - 4i) ]

Using the distributive property and the fact that ( i^2 = -1 ), we can expand and simplify this expression:

[ z_1 \times z_2 = 8 \times 1 - 8 \times 4i + 3i \times 1 - 3i \times 4i ] [ z_1 \times z_2 = 8 - 32i + 3i - 12i^2 ] [ z_1 \times z_2 = 8 - 32i + 3i + 12 ] [ z_1 \times z_2 = 20 - 29i ]

So, the simplified product of ( z_1 ) and ( z_2 ) is ( 20 - 29i ).

Answer 13

amgnsla

Answer 14

?????