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Mathematics 15 Online
BexleyBrooks:

Justin graphed the points (2,6) (3,12) (4,20) and (5,30) He says that relation is a linear function. Is Justin correct??

Hangry53:

proly

luhivqqcherry:

Justin is incorrect .

luhivqqcherry:

That is because the ratios are not constant .

umm:

A linear function is a rule that helps draw a straight line on a graph. To check if a relation is linear, calculate the differences in the y-values for consecutive x-values. If these differences are consistently the same, the relation is linear.

Aliciaa:

Explanation: No, Justin is not correct. A linear function is a function whose graph forms a straight line. In order to determine if a relation is linear, we need to check if the difference in the y-values is proportional to the difference in the x-values

Treeko:

i have no idea, sorry, but these people have the answers!

toga:

To determine whether the given relation is a linear function, we need to check if the rate of change between any two points is constant. Let's calculate the rate of change between the first two points: (6-12)/(2-3) = -6 Now, let's calculate the rate of change between the second and third points: (12-20)/(3-4) = -8 And, the rate of change between the third and fourth points: (20-30)/(4-5) = -10 As we can see, the rate of change is not constant, which means that the given relation is not a linear function. Therefore, Justin is incorrect.

Ragtagirly:

@toga wrote:
To determine whether the given relation is a linear function, we need to check if the rate of change between any two points is constant. Let's calculate the rate of change between the first two points: (6-12)/(2-3) = -6 Now, let's calculate the rate of change between the second and third points: (12-20)/(3-4) = -8 And, the rate of change between the third and fourth points: (20-30)/(4-5) = -10 As we can see, the rate of change is not constant, which means that the given relation is not a linear function. Therefore, Justin is incorrect.
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