HELP @rthrth

Question

HELP @rthrth

Uniful3 · Answer

attachment

Uniful3 · Answer

T^T

Aliciaa · Answer

I hate delta Math I feel your pain

Uniful3 · Answer

@aliciaa wrote:

I hate delta Math I feel your pain

T^T

rthrth · Answer

the equation of a line can be written as
y=mx+b

m is the slope
b is the y-intercept

rthrth · Answer

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

Uniful3 · Answer

@rthrth wrote:

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

hmm

Aratox · Answer

@rthrth wrote:

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

Blud is a genius o-o

Uniful3 · Answer

@uniful3 wrote:

@rthrth wrote:

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

hmm

so I would have to use..m =(y2 - y1) (x2 - x1)?

rthrth · Answer

@uniful3 wrote:

@rthrth wrote:

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

hmm

so I would have to use..m =(y2 - y1) (x2 - x1)?

yes

Uniful3 · Answer

@rthrth wrote:

@uniful3 wrote:

@rthrth wrote:

m (the slope) is rise over run. How much it increase in the y direction over increase in x direction$$\frac{ rise }{ run }$$

hmm

so I would have to use..m =(y2 - y1) (x2 - x1)?

yes

yay

rthrth · Answer

the equation to the first line: y=1/2x+3
the blue is where the line crosses the y-axis

Uniful3 · Answer

@rthrth wrote:

the equation to the first line: y=1/2x+3 the blue is where the line crosses the y-axis

okii

rthrth · Answer

what do you get as the equation for your graph

Uniful3 · Answer

@rthrth wrote:

what do you get as the equation for your graph

y = (1/2)x + 3?

rthrth · Answer

i mean on your first attachment on delta math

Uniful3 · Answer

@rthrth wrote:

i mean on your first attachment on delta math

oh

Uniful3 · Answer

@rthrth wrote:

i mean on your first attachment on delta math

TTT idkk

rthrth · Answer

pick two points on the line, and plug the coordinates into this   m =(y2 - y1)  (x2 - x1)

Uniful3 · Answer

@rthrth wrote:

pick two points on the line, and plug the coordinates into this m =(y2 - y1) (x2 - x1)

could they be any points on the line?

rthrth · Answer

@uniful3 wrote:

@rthrth wrote:

pick two points on the line, and plug the coordinates into this m =(y2 - y1) (x2 - x1)

could they be any points on the line?

yes

Uniful3 · Answer

@rthrth wrote:

@uniful3 wrote:

@rthrth wrote:

pick two points on the line, and plug the coordinates into this m =(y2 - y1) (x2 - x1)

could they be any points on the line?

yes

hmm

Uniful3 · Answer

@uniful3 wrote:

@rthrth wrote:

@uniful3 wrote:

@rthrth wrote:

pick two points on the line, and plug the coordinates into this m =(y2 - y1) (x2 - x1)

could they be any points on the line?

yes

hmm

(4, -1)

rthrth · Answer

@uniful3 wrote:

@rthrth wrote:

@uniful3 wrote:

@rthrth wrote:

pick two points on the line, and plug the coordinates into this m =(y2 - y1) (x2 - x1)

could they be any points on the line?

yes

hmm

(4, -1)

it needs to be on the line, ex. (5, -6), (1, -2), (4, -5)

Uniful3 · Answer

can i use the examples?

rthrth · Answer

yeah, ofc

Uniful3 · Answer

@rthrth wrote:

yeah, ofc

oki

Uniful3 · Answer

@rthrth wrote:

yeah, ofc

tyy

1 attachment

1 attachment