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An expression is shown below: 10n3 − 15n2 + 20xn2 − 30xn Part A: Rewrite the expression by factoring out the greatest common factor. Part B: Factor the entire expression completely. Show the steps of your work.
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Part A: The greatest common factor of the expression is 5n. 5n(2n^2 - 3n + 4x^2 - 6x) Part B: To factor the expression completely, we need to look for common factors in each pair of terms. 5n(2n^2 - 3n) + 5n(4x^2 - 6x) 5n(n(2n - 3) + 5x(2x - 3)) 5n(n + 5x)(2n - 3) Therefore, the completely factored expression is 5n(n + 5x)(2n - 3).
@aratox wrote:
Part A:
The greatest common factor of the expression is 5n.
5n(2n^2 - 3n + 4x^2 - 6x)
Part B:
To factor the expression completely, we need to look for common factors in each pair of terms.
5n(2n^2 - 3n) + 5n(4x^2 - 6x)
5n(n(2n - 3) + 5x(2x - 3))
5n(n + 5x)(2n - 3)
Therefore, the completely factored expression is 5n(n + 5x)(2n - 3).
@d14610 wrote:
@aratox wrote:
Part A:
The greatest common factor of the expression is 5n.
5n(2n^2 - 3n + 4x^2 - 6x)
Part B:
To factor the expression completely, we need to look for common factors in each pair of terms.
5n(2n^2 - 3n) + 5n(4x^2 - 6x)
5n(n(2n - 3) + 5x(2x - 3))
5n(n + 5x)(2n - 3)
Therefore, the completely factored expression is 5n(n + 5x)(2n - 3).
@aratox wrote:
@d14610 wrote:
i got 2 more questions like this if you could help i'd appreciate it big time
thanks goat
@aratox wrote:
Part A:
The greatest common factor of the expression is 5n.
5n(2n^2 - 3n + 4x^2 - 6x)
Part B:
To factor the expression completely, we need to look for common factors in each pair of terms.
5n(2n^2 - 3n) + 5n(4x^2 - 6x)
5n(n(2n - 3) + 5x(2x - 3))
5n(n + 5x)(2n - 3)
Therefore, the completely factored expression is 5n(n + 5x)(2n - 3).
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