Right triangle ABC is located at A (−1, −2), B (−1, 1), and C (−5, 1) on a coordinate plane. What is the equation of a circle A with radius segment AC?

(x + 1)2 + (y + 2)2 = 9
(x + 5)2 + (y − 1)2 = 16
(x + 1)2 + (y + 2)2 = 25
(x + 5)2 + (y − 1)2 = 25

Question

Right triangle ABC is located at A (−1, −2), B (−1, 1), and C (−5, 1) on a coordinate plane. What is the equation of a circle A with radius segment AC?

(x + 1)2 + (y + 2)2 = 9
 (x + 5)2 + (y − 1)2 = 16
 (x + 1)2 + (y + 2)2 = 25
 (x + 5)2 + (y − 1)2 = 25

Aratox · Answer

Do you have an online/paper representation of the graph? If you do, please post it

Darkest · Answer

Uum I ain't done this in a little minute lemme think

imloyalipromise · Answer

@aratox wrote:

Do you have an online/paper representation of the graph? If you do, please post it

there is no graph its just that

Darkest · Answer

C

hannahj · Answer

(x +1)^2 +(y +2)^2 = 25

imloyalipromise · Answer

@hannahj wrote:

(x +1)^2 +(y +2)^2 = 25

thanks

HotPockets14 · Answer

@hannahj wrote:

(x +1)^2 +(y +2)^2 = 25

this is the correct answer

Luigi0210 · Answer

@hannahj wrote:

(x +1)^2 +(y +2)^2 = 25

And where's the explanation..?

hannahj · Answer

The center of the circle is located at point A, which is (-1,-2). The radius of the circle is the length of segment AC. First, find the length of the radius by calculating the distance between A and C using the distance formula: √[(x2-x1)² + (y2-y1)²] = √[(-5 - (-1))² + (1 - (-2))²]

= √[(-4)² + 3²]

= √[16 + 9]

= √25

= 5.

Then, the equation of the circle is (x-h)² + (y-k)² = r², where (h,k) is the center and r is the radius.

Substituting (-1,-2) for (h,k) and 5 for r, the equation becomes (x+1)² + (y+2)² = 5², or

(x + 1)² + (y + 2)² = 25. So, the answer is option C.

L8RAaronOnTop · Answer

W