Can someone explain this to me Pic below
In the given equilibrium reaction: F − ( 𝑎 𝑞 ) + H 2 O ⇌ HF ( 𝑎 𝑞 ) + OH − ( 𝑎 𝑞 ) F − (aq)+H 2 O⇌HF(aq)+OH − (aq) If water is acting as an acid, it means that it is donating a proton (H + + ) to another species. In this case, water is donating a proton to the fluoride ion (F − − ). Therefore, the correct answer is: B. The water donates H + + to F − − .
Idk y it did tht
No not from google. My friends text
One thing you should take notice of is the charges on the elements as it transitions from one side to the other. The fluorine (\(\color{red}{F} \)) goes from \(\color{red}{-1} \) to a neutral charge of \(\color{green}{0} \), meaning it gained a proton. In this case, it gained a hydrogen ion (aka a proton). The water, which was acting as an acid, lost a proton going from \(\color{green}{0} \) to \(\color{red}{-1} \). So you can conclude that the water molecule donated a proton/hydrogen \( H^+ \) to the ion Florine \( F^- \)
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