is this correct i did this problem Calculate the force exerted by Jupiter on its moon Europa and the force exerted by Europa on Jupiter. The mass of Jupiter is about 1.90 × 1027 kg, and the mass of Europa is about 4.80 × 1022 kg. The distance between their centers of mass is 7.43 × 1011 m. and used the F=G times m1 times m2/ r^2 and i got 1.10 (ect) times 10^15N

Question

is this correct i did this problem Calculate the force exerted by Jupiter on its moon Europa and the force exerted by Europa on Jupiter. The mass of Jupiter is about 1.90 × 1027 kg, and the mass of Europa is about 4.80 × 1022 kg. The distance between their centers of mass is 7.43 × 1011 m. and used the  F=G times m1 times m2/ r^2 and i got 1.10 (ect) times 10^15N

CHRiiis · Answer

Idk I'm dumb

lolboooohruuu · Answer

@chriiis wrote:

Idk I'm dumb

ur so silly !

NorthLegacyKing · Answer

you need to make small adjustments on the exponent but everything else looks correct

lolboooohruuu · Answer

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

NorthLegacyKing · Answer

@lolboooohruuu wrote:

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

yes that is correct

lolboooohruuu · Answer

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

yes that is correct

I have another one : Suppose a spacecraft is orbiting 3.92 × 105 m above the surface of Mars. Calculate the magnitude of Mars’ gravitational field and the approximate acceleration due to gravity experienced by the spacecraft. (The mass of Mars is 6.39 × 1023 kg, and its radius is 3.40 × 106 m.) and i got ( 14.45289 times 10^5) or 1445289.75779

NorthLegacyKing · Answer

@lolboooohruuu wrote:

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

yes that is correct

I have another one : Suppose a spacecraft is orbiting 3.92 × 105 m above the surface of Mars. Calculate the magnitude of Mars’ gravitational field and the approximate acceleration due to gravity experienced by the spacecraft. (The mass of Mars is 6.39 × 1023 kg, and its radius is 3.40 × 106 m.) and i got ( 14.45289 times 10^5) or 1445289.75779

looks like you got a miscalculation and got the big number by mistake the correct value should be about 2.97 m/s² but it's a easy slip up in math especially with big numbers like this

lolboooohruuu · Answer

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

yes that is correct

I have another one : Suppose a spacecraft is orbiting 3.92 × 105 m above the surface of Mars. Calculate the magnitude of Mars’ gravitational field and the approximate acceleration due to gravity experienced by the spacecraft. (The mass of Mars is 6.39 × 1023 kg, and its radius is 3.40 × 106 m.) and i got ( 14.45289 times 10^5) or 1445289.75779

looks like you got a miscalculation and got the big number by mistake the correct value should be about 2.97 m/s² but it's a easy slip up in math especially with big numbers like this

is it because mars has different gravitational force?

NorthLegacyKing · Answer

@lolboooohruuu wrote:

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

@lolboooohruuu wrote:

@northlegacyking wrote:

you need to make small adjustments on the exponent but everything else looks correct

ok i see, i checked and the exponent is 16 right?

yes that is correct

I have another one : Suppose a spacecraft is orbiting 3.92 × 105 m above the surface of Mars. Calculate the magnitude of Mars’ gravitational field and the approximate acceleration due to gravity experienced by the spacecraft. (The mass of Mars is 6.39 × 1023 kg, and its radius is 3.40 × 106 m.) and i got ( 14.45289 times 10^5) or 1445289.75779

looks like you got a miscalculation and got the big number by mistake the correct value should be about 2.97 m/s² but it's a easy slip up in math especially with big numbers like this

is it because mars has different gravitational force?

yeah mars has weaker gravity and so the force is much smaller then Earth's