If 2x2(5-x)(3x+2) = 0, then what is the sum of all of the possible values of x?

Question

Gdub08 · Answer

13/2 ? I think

SnowyBreaks · Answer

no its not

SnowyBreaks · Answer

okay give me one second

SnowyBreaks · Answer

so I got the answer 2.

SnowyBreaks · Answer

-2

SnowyBreaks · Answer

Your doing eighth grade math correct?

SnowyBreaks · Answer

Recalculated and the answer should be 2 and 1/3

SnowyBreaks · Answer

2 1/3

SnowyBreaks · Answer

always multiply the 2 by everything in the parenthesies

SnowyBreaks · Answer

like 2(5-x)(3x+2) 
2x5=10, 2 times -x equals -2x
2 times 3x=6x and 2x2=4
Next your gonna add 10 and 4 and that gets you 14. Then add 2x+-2x+6x

SnowyBreaks · Answer

And that will get you 6x still.

SnowyBreaks · Answer

Then divided both 6x by -6x and 14 by -6x

SnowyBreaks · Answer

I hope this is helpful

Gdub08 · Answer

@snowybreaks wrote:

I hope this is helpful

thank youuuu.

SnowyBreaks · Answer

@gdub08 wrote:

@snowybreaks wrote:

I hope this is helpful

thank youuuu.

no problem

V4MPZSKII · Answer

Im too dumb for this

Gdub08 · Answer

@v4mpzskii wrote:

Im too dumb for this

lol

jhonyy9 · Answer

$$2x^2(5-x)(3x-2)=0$$

2x^2 = 0 => x=0

5-x=0 => x=5

3x-2=0 => 3x=2 => x=2/3

and now the sum of all these values of x = 0+5+2/3

$$x = 5 + \frac{ 2 }{ 3 }$$

$$x = \frac{ 3*5 +2 }{ 3 }$$

$$x = \frac{ 17 }{ 3 }$$