@gucchi wrote: no guesses dude mb

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Gucchi:

chem help

1 year ago

Gucchi:

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1 year ago

Gucchi:

am i right with C here?

1 year ago

Gdub08:

@gucchi wrote:

am i right with C here?

Yes I think

1 year ago

Gucchi:

no guesses dude

1 year ago

sllo:

The correct answer is 1.71x 10^24 atoms ag :)

1 year ago

sllo:

So yes your correct

1 year ago

Gucchi:

wait can you explain why rq

1 year ago

Gdub08:

@gucchi wrote:

no guesses dude

1 year ago

Glorious:

@gucchi wrote:

am i right with C here?

1. Convert grams to moles: Divide the mass of silver by its molar mass. The molar mass of silver is 107.87 g/mol. $307 \ g \div 107.87 \ g/mol = 2.85 \ mol$ 2. Convert moles to atoms: Multiply the number of moles by Avogadro's number, which is 6.022 x 10^23 atoms/mol. $2.85 \ mol \times 6.022 \times 10^{23} \ atoms/mol = 1.71 \times 10^{24} \ atoms$ This means that Mirabel has 1.71 x 10^24 atoms of silver.

1 year ago

Glorious:

@gucchi ^

1 year ago

sllo:

For sure, Mirabel has 307 grams of silver, to find th enumber of atoms you covert the grams to moles, using silver's molar mass (107.87/mol) which gives 2.85 moles. then multiplyby avogadro's number by (6.022 x 10^23) atoms/mol, determing the total, atoms, approximately is 1.71x 10^24 atoms. Let me know if you want me to explain it more :)

1 year ago

Gucchi:

thank you

1 year ago

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