Mathematics
OpenStudy (anonymous):

Definite Integral: The velocity of a moving particle is defined by the function v(t)=3t-6t^2cm/s What is the distance covered between t=2sec to t=4sec?

You can set this up like this: $s = \int_2^4 v(t)dt = \int_2^4 3t - 6t^2 dt$ Can you solve that?