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OpenStudy (anonymous):
Definite Integral: The velocity of a moving particle is defined by the function v(t)=3t-6t^2cm/s What is the distance covered between t=2sec to t=4sec?
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OpenStudy (shadowfiend):
You can set this up like this: \[s = \int_2^4 v(t)dt = \int_2^4 3t - 6t^2 dt\] Can you solve that?
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