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OpenStudy (anonymous):

can anyone help with my questions its physics???

OpenStudy (bahrom7893):

i can try

OpenStudy (anonymous):

ok do you get my question

OpenStudy (bahrom7893):

yes and i said i can try.. aka i can try to help, post the question then we'll see

OpenStudy (anonymous):

F=time generating force felt by the earth due to another object in space. m1=mass of the earth=5.98x10E24kg m2=mass of the in space R=distance between the earth and object (in meters) G=universal gravitational constant=6.6720x10E negative11 mE3/kg*sE2 a=radius of the earth=6400km

OpenStudy (anonymous):

So what are you looking forr???

OpenStudy (anonymous):

F=2GM1M2a/R E3 This is the formula

OpenStudy (anonymous):

ok well i have to calculate the tide generating force due to the sun and the force due to the moon

OpenStudy (anonymous):

i have to use the following numbers:

OpenStudy (anonymous):

Mm=mass of the moon=7.42*10E22 kg Ms= mass of the sun=1.83*10E30 kg Rm= distance between the moon and earth= 3.840*10E5 km Rs= distance between sun and earth=1.495*10E8

OpenStudy (anonymous):

E means exponent

OpenStudy (bahrom7893):

can u post the formula the regular way? its kinda confusin this way, via insert equation?

OpenStudy (anonymous):

i can't do it that way.... but it is F=2GM expo1 M expo2 a/ R expo3

OpenStudy (bahrom7893):

\[F = [(2G)M^{1}M ^{2}\times a] / R^3\]

OpenStudy (bahrom7893):

Like that?

OpenStudy (anonymous):

yes (:

OpenStudy (bahrom7893):

okay afk...

OpenStudy (bahrom7893):

m2=mass of the in space -- mass of the what?

OpenStudy (bahrom7893):

And im sure ur formula is wrong. This is the right one: http://upload.wikimedia.org/math/0/f/3/0f36df929ac9d711a8ba8c5658c3bfee.png

OpenStudy (anonymous):

mass of the object that is the formula they gave us

OpenStudy (bahrom7893):

Im sure u copied it wrong! It is Msub 1 and Msub 2, the universal gravitaional constant formula!

OpenStudy (anonymous):

ok i probly did. does it make sense with ur formula??

OpenStudy (bahrom7893):

yeah

OpenStudy (anonymous):

ok think it is that one

OpenStudy (anonymous):

did u figure out the problem?

OpenStudy (bahrom7893):

workin man

OpenStudy (bahrom7893):

and my equation was wrong too

OpenStudy (anonymous):

girl, but ok sorry keep helping me thanks so much

OpenStudy (bahrom7893):

k lol sorry

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