Question

[\sqrt{d ^{2}-19} -2d + 11=0

Answer 1

wait can u repost the question?

Answer 2

is it the same that i answered?

Answer 3

no i typed it wrong the first time

Answer 4

So can u repost it, i still dont see the right question

Answer 5

\[\sqrt{d ^{2}-19}-2d+11=0\]

Answer 6

okay

Answer 7

\[\sqrt{d^2 - 19} = 2d - 11\]
Move -2d and 11 to the other side

Answer 8

Square both sides:
\[d^2 - 19 = (2d - 11)^2\]

Answer 9

Rewrite the right side as:
\[d^2 - 19 = 4d^2 - 44d + 121\]

Answer 10

Rewrite in form of a regular quadratic equation and simplify:
\[3d^2 - 44d +130 = 0\]

Answer 11

Can u finish solving for d?

Answer 12

yes, Do you have time for one more. It is similar with a cube root?

Answer 13

yeah

Answer 14

in that case u cube both sides, same method

Answer 15

\[\sqrt[3]{8v ^{2}-6v}+1=0\]

Answer 16

so move one over to the right and cube both sides to get:
8v^2 - 6v = (-1)^3
8v^2 - 6v = -1. Solve for V

Answer 17

I get \[8v^{2}-6v+1\]

Answer 18

yeah 8v^2 - 5v + 1 = 0

Answer 19

solve for v

Answer 20

thanks