Mathematics
8 Online
OpenStudy (anonymous):
Inverse of Log base 4 of x
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OpenStudy (anonymous):
y=4^x\[f(x)=4^x\] ?
OpenStudy (anonymous):
Yes Perto! xD
OpenStudy (anonymous):
*gasp i was thinking that!
well there's one i got right on the test..
OpenStudy (anonymous):
Now, try this one!
Log base 2 of x + 3
OpenStudy (anonymous):
the inverse of that?
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OpenStudy (anonymous):
yesh!
OpenStudy (anonymous):
f(x)= 2^(x+3)
OpenStudy (anonymous):
?
OpenStudy (anonymous):
Nope!
OpenStudy (anonymous):
D:
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OpenStudy (anonymous):
f(x)= 2^x ?
OpenStudy (anonymous):
wait a sec!
OpenStudy (anonymous):
wait lemme see!
OpenStudy (anonymous):
where's hanh?
OpenStudy (anonymous):
The answer is
y = 2^x - 3
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OpenStudy (anonymous):
why minus?
OpenStudy (anonymous):
can you show me how you did that
OpenStudy (anonymous):
cuz its the inverse
OpenStudy (anonymous):
darn..that means i probably got that wrong in the test. :\
OpenStudy (anonymous):
Okie! So it's:
y = Log base e of x + 3, NOT (x+3)
So it's
2^y = x + 3
There fore, 2^x - 3 = y
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OpenStudy (anonymous):
id remember if i got that right
OpenStudy (anonymous):
base 2*
OpenStudy (anonymous):
next problem
OpenStudy (anonymous):
Log base x of 3x
OpenStudy (anonymous):
thats wierd
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OpenStudy (anonymous):
x ^ y = 3x
Inverse = x^x = 3y, so it's
y = (x^x) / 3
OpenStudy (anonymous):
thats wierd
OpenStudy (anonymous):
okay, I'll change base x to base 2
OpenStudy (anonymous):
why?
OpenStudy (anonymous):
so that you won't be confuse with which x to switch
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OpenStudy (anonymous):
2^y or x^y in the original = 3x
Inverse = 2^x original x^x = 3y
so divide both side by 3 to get y
y = (2^x)/3 or (x^x)/3 in the original