Question

5+3[1+2(2x-3]=6(x+5)

Answer 1

I'm assuming you mean 5+3(1+2(2x-3)) = 6(x+5)

Answer 2

this is another case where you need to distribute

Answer 3

start with the right side, what is 6(x+5) ?

Answer 4

yes

Answer 5

6x+30?

Answer 6

yep!

Answer 7

ok now start from the inside out on the left hand side

Answer 8

do u always start with the right side

Answer 9

so what is 2(2x-3)

Answer 10

well, I think generally start from inside out

Answer 11

as in inner-most thing that needs to be expanded

Answer 12

4x-6

Answer 13

ok great, so to recap, so far we have:
5 + 3(1 + 4x - 6) = 6x + 30

Answer 14

gotcha

Answer 15

so to make it easier on yourself, how about combing like terms in the parens, so what is (1+4x - 6) ?

Answer 16

5x-6 or do u break that down further

Answer 17

well, that's not correct

Answer 18

you can't combine 1 and 4x, since you don't know what 4x

Answer 19

but you can combine 1 and -6

Answer 20

(by adding them)

Answer 21

-5

Answer 22

if it had been (1x +4x -6) you would have been correct, since the 1 and 4 are both x's

Answer 23

right so the middle is now -5 + 4x, or 4x - 5

Answer 24

so now you have : 5 + 3(4x - 5) = 6x + 30

Answer 25

what is your next step?

Answer 26

5+12x-15=6x+30

Answer 27

great =)

Answer 28

so can you combine anything on the left side?

Answer 29

5 and 15 which is -10

Answer 30

yep =), so now what do you have?

Answer 31

is it 12x-10=6x+30

Answer 32

exactly

Answer 33

so now the basic rule of algebra, and equations/equalities in general - you can perform any operation to both sides of an equation and still have the equatoin be true (satisfied)

Answer 34

the reason that's powerful is because it allows you to eventually get x all by itself

Answer 35

so let's say you wanted to get 12x by itself on the left hand side

Answer 36

what could you add to both sides to make that happen?

Answer 37

add 10

Answer 38

yep, and what do you get if you add 10 to both sides

Answer 39

12x=6x+40

Answer 40

exactly. ok , so remember, when you're solving for a variable (in this case x), the idea is to get all of that variable to one side, and then eventually just one instance of that variable by itself (x)

Answer 41

so what could you subtract from both sides, to get all of the x's in one place?

Answer 42

would u minus 6x

Answer 43

exactly, and then what you get?

Answer 44

6x=40 then i divided by 6 both sides

Answer 45

yep!

Answer 46

good work

Answer 47

6.6?

Answer 48

yeah, or you could write it as a fraction

Answer 49

so x = 40/6

Answer 50

and that can be reduced if you divide both top and bottom by 2

Answer 51

so x = 20/3

Answer 52

so now that you think x = 20/3

Answer 53

thank u so much i think im getting it sum what lol

Answer 54

you stick it back into the original equation (or just use 6.666666 to check in your calculator)

Answer 55

and if the equation is true, then you know you got it right

Answer 56

so for these types of problems, try expanding everything out first

Answer 57

and then just keep doing the same operations on both sides until you conveniently get all the x's (or whatever you're solving for) in one place

Answer 58

and then just get the value for one x by dividing

Answer 59

after a while, you'll start seeing some shortcuts if they're there

Answer 60

for example, if you had 3(x+3) = 12

Answer 61

you wouldn't *have* to expand first

Answer 62

you could just divide both sides by 3

Answer 63

to get x+3 = 4

Answer 64

and then subtract 3 from both sides to get x=1

Answer 65

but seeing that will come with practice

Answer 66

good luck!

Answer 67

oh ok thanks a bunch !!!!

Answer 68

yep np