Question

Find the equation of the tangent line at the point a.
1. f(x)=1-x^3 a=(0,1)

Answer 1

ok so for this question, just take a derivative. Then you get f'(x)=-3x^2. Now plug in x=0 cause that's the point in question. Then you get f'(x) = 0. So now we know that the tangent slope must be 0. So the equation of the tangetn line has the form y=mx+b or y=b since m=0. Now to find b, plug the point in question again. I don't see any x in y=b, but I do see a y. Plug y = 1. Then b=1. So tangent line is y=1

Answer 2

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